1T 2011 høst LØSNING
Fra Matematikk.net
DEL EN
Oppgave 1:
a)
<tex> \frac{x^2-25}{x^2+10x+25} = \frac{(x+5)(x-5)}{(x+5)(x+5)} = \frac{x-5}{x+5}</tex>
b)
<tex> 3^{2x-1} = 1 \ 3^{2x-1} = 3^0 \ 2x-1 = 0 \ x= \frac 12</tex>
DEL EN
<tex> \frac{x^2-25}{x^2+10x+25} = \frac{(x+5)(x-5)}{(x+5)(x+5)} = \frac{x-5}{x+5}</tex>
<tex> 3^{2x-1} = 1 \ 3^{2x-1} = 3^0 \ 2x-1 = 0 \ x= \frac 12</tex>